The perimeter of a rectangular field is 60 meters its area is 200 square meters find its dimensions

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The perimeter of a rectangular field is 60 meters its area is 200 square meters find its dimensions

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The Brainliest Answer!

lw = 200

2l + 2w = 60 --------- l = 30 - w

I'll use the substitution method. Since l = 30 - w, we can substitute the length to 30 - w to lw = 200.

(30 - w) w = 200

-w² + 30w = 200 ------------- transpose -w² + 30w

w² - 30w + 200 = 0 --------------- use factoring

(w - 20) (w - 10) = 0 -------------- then equate each factor to zero

w - 20 = 0 w - 10 = 0

lw = 200 lw = 200

l (20) = 200 l (10) = 200

l (20)/20 = 200/20 l (10)/10 = 200/10

So the answers to the problem are:

Width = 20 then length = 10 or

width = 10 then length = 20

width = 10 then length = 20