Answers

2014-05-07T19:53:26+08:00
If x = 0 then
Y = (0)^4 - 4(0)^3 + 16(0)^2 -2
Y = 0 - 4(0) + 16(0) - 2
Y = - 2
0
where is tangent and normal lines ?
oh sorry I thought you were just looking for the value of Y.
find the equation of the tangent and normal line