Answers

2014-11-01T14:58:44+08:00
Using the sum of arithmetic progression you'll have:
S_n = [2a_1 +(n-1)d]  \frac{n}{2}
where a1=2
              n=50
              d=2
S_n = [2(2) + (50-1)(2)] \frac{50}{2}
S_n = [4 + 49(2)](25)
S_n = 2,550
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