are you really asked of the x and y intercepts or just the values of x and y?

yes

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are you really asked of the x and y intercepts or just the values of x and y?

yes

Log in to add a comment

2x - y = 1 ----equation 2

from equation 1

x - y = 2

x = y + 2 ----equation 1'

substitute equation 1' to equation 2

2x - y = 1

2(y+2) - y = 1

2y + 4 - y = 1

y = 1 - 4

y = -3

substitute y = -3 to equation 1'

x = y + 2

x = -3 + 2

x = -1

therefore the two lines intersect at (-1,-3)

for the x and y intercepts of each line:

line 1:

x - y = 2

for x-intercept, y=0

x - 0 = 2

x = 2

for y-intercept, x=0

x - y = 2

0 - y = 2

-y = 2

y = -2

therefore the x and y intercepts of the first line are the points (2,0) and (0,-2) respectively

line 2:

2x - y = 1

for x-intercept, y=0

2x - 0 = 1

2x = 1

x = 1/2

for y-intercept, x=0

2(0) - y = 1

-y = 1

y = -1

therefore the x and y intercepts of the second line are the points (1/2,0) and (0,-1) respectively