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I think we will solve for x. 
so 2(cube root of 1-3x)=-4 
we will cube both side 
so the radical will now cancel
so "x=3" then if we substitute the value of x from the given equation we will get -4
2 5 2
2∛1-3x = -4 Divide both side by 2
∛1-3x = -2   to cancel the radical raise both side by 3
the equation will be,
1-3x= -8
transpose 1 to the right
-3x=-9 divide the equation by-3
0 0 0
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