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A spherical piece of metal has a radius of 0.250 m and a mass of 503.0 kg. What is its specific gravity?

Help me answer this question :)

1
by joel12

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Help me answer this question :)

by joel12

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First, you need to find the volume of the metal.

V = 4/3 πr³ = 4/3 π(0.25)³

Density is equal to g/cm³ or kg/m³. Therefore, the density of the metal is

503 kg /[4π(0.25)³ /3] m³ <--Let this be equal to d

The specific gravity (SG) is the ratio of its density to water. The density of water is 1000kg/m³. <--I'll let this equal to w

So, SG = d/w <--just plug in the values you computed

Note: Sorry I don't have a calculator with me

V = 4/3 πr³ = 4/3 π(0.25)³

Density is equal to g/cm³ or kg/m³. Therefore, the density of the metal is

503 kg /[4π(0.25)³ /3] m³ <--Let this be equal to d

The specific gravity (SG) is the ratio of its density to water. The density of water is 1000kg/m³. <--I'll let this equal to w

So, SG = d/w <--just plug in the values you computed

Note: Sorry I don't have a calculator with me