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from a given position an observer notes that at the angle of elevation of a rock is 47 degrees. After walking 1000 feet towards the rock, up a slope of

32 degrees, he finds the angle of elevation to be 75 degrees. find the vertical distance of the rock above each point of observation.



Let H be the vert dist. of the rock from the first observer I and h from obsever II and x horizontal distance.H = x tan 47   also H=  (x - 1000cos32)tan75 + 1000sin 32Solve for x     x = 990.73 feet    H = x tan 47 = 1062.4 feeth = H - 12.5000 sin32 = 532.5 feet
(c)Gloria Katherine
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