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For breakfast Amanda has oatmeal with fruit. She has 3 flavors of oatmeal: brown sugar, maple, and cinnamon. She has 3 types of fruit: raisins,

cranberries, and blueberries. Each flavor of oatmeal and each type of fruit has an equal chance of being selected. What is the probability that Amanda randomly selects cinnamon oatmeal with raisins?


Simple math.

Probability is equal to the number of ways it can happen over the total number of outcomes.

Or simple

P = n1 + n2 + n3... / nTotal

However in you question, you have used the word "and" that represent multiplication instead of "or" that represents addition.

So we need to change the formula like this

P = n1 * n2 * n3... / NTotal

So we just need multiply the number of oatmeal to fruits to get nTotal. Since we have two different category.

So we have 3 * 3 = 9 total possibility

And we need to multiply 1 cinnamon oatmeal to 1 raisin fruit

That will be 1


P = 1/9

So Amanda can have the probability of having cinnamon with raisin of 1/9 or 0.11.

You can just simply make a table for this.

For oatmeals,

S for brown sugar, M for maple and C for Cinnamon

For fruits,

R for raisins, C for cranberries and B for blueberries

OATMEAL  |     SR     |    SC    |     SB    |
                  |    MR    |    MC    |    MB     |
                  |    CR     |    CC    |    CB      |

We have a total of 9 outcomes and CR represents cinnamon with raisins.

I hope it helps.
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