Answers

2014-05-18T18:12:42+08:00
Set  (8d^{6} j^{3})^{3} = x
 and (3 s^{10} t^{5} )^{3} = y 

therefore: x³ + y³ 
= (x+y)(x²-xy+y²) 
= [ (8d^6 j^3) + (3s^10 t^5) ] [ (8d^6 j^3)² + (8d^6 j^3)(3s^10 t^5) + (3s^10 t^5)² ]
= [ (2d²j)³ +(3s^10 t^5) ] [ (2d²j)^6 + (2d²j)³(3s^10 t^5) + (3s^10 t^5)² ]

729-b^6c^12 
= 9³-(b²c^4)³
=[9 - (b²c^4)] [81+81(b²c^4)+(b²c^4)²] 
=[ 3² - (bc²)² ] [81+81(b²c^4)+(b²c^4)²] 
=[ 3 + (bc²)] [ 3 - (bc²) ] [81+81(b²c^4)+(b²c^4)²] 
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