# Find the equation of a circle passing through the intersection of 4x+y-4=0 and x-y-6=0 with center (-1,-3)

2
by catlimay

2014-05-15T13:10:42+08:00

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(x+1)^2 +(y+3)^2 =8.08
the point of intersection between the two lines is (6/5, -24/5)
2014-05-15T13:11:34+08:00

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
4x+y-4=0
x-y-6=0

Using the process of elimination, we will get x=2 and y=-4. Therefore, the circle passes through point (2, -4).

To find the radius of the circle, use the distance formula.
d =  = √10

The equation of a circle with centre at (h,k) and radius r is
(x-h)² + (y-k)² = r²

Therefore, the equation of the circle is
(x+1)² + (y+3)² = 10

In general form,

x² +2x +y² +6y = 0

please disregard the A. I can't seem to remove it