I'm almost brain-dead thinking for the answer in this question.

I'm thinking of using quadratic formula for this. it can be write as 2x^2 - 10x + 16 = 0

oh wait it should be 2x^2 = 16 -10x. I'll try to solve it later

16 less than 10 times the number is translated as 10x-16. You will have it as 2x^2 = 10x - 16.. dividing the whole equation by 2 you'll have x^2-5x+8=0.. it can't be factored using square property hence you only have 1,2,4 and 8 as the factors of 8 and none would satisfy the middle term. using quadratic formula to find the factors, you will have the factors as [x-(5/2+sqrt7/2i)] and [x-(5/2-sqrt7/2i)]... (-_-)!

haha sorry about it... then my first equation is right than my second. I can't re edit my answer below

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