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A triangle ABC has a line that contains both points B and C which measures 45m far from each other. The distance of point A from point C is twice the

distance of points B and C less than 15. The supplement of angle between the two sides is their sum. Find angles A, Angle B and side c. Hellpppppp


A= tan^-1(45/75) = 30.96° B= tan^-1(75/45) = 59.04° c= 75+45 = 120 m
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