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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

I have a trouble understanding our lesson this week. Please help me out.I want a clear explanation how to solve it. The problem goes like this:

A square is a quadrilateral with four equal sides. The are of a square is equal to the square of its side. The diagonal of a square is a line segment joining any two non-consecutive sides. Find the area of a square and the length of its diagonal whose vertices are: (3,1), (-1,5), (-5,1) (-1,-3).

(-1,5) and (-1,-3) are the ends of a vertical line. Since (3,1) is not
at the same y-coordinate as either of those, the vertical line must be a
diagonal. It has length=8.
Since the diagonal has length 8, its sides have length 4√2, giving an area of 32.
Knowing that the other diagonal is horizontal and has length=8, it
should be easy to plot the missing vertex and draw the square.
For what it's worth, the diagonal is a line segment joining two non-consecutive vertices, not sides.

LOL i wished i have explained well. *5th grader here*