I have a trouble understanding our lesson this week. Please help me out.I want a clear explanation how to solve it. The problem goes like this:
A square is a quadrilateral with four equal sides. The are of a square is equal to the square of its side. The diagonal of a square is a line segment joining any two non-consecutive sides. Find the area of a square and the length of its diagonal whose vertices are: (3,1), (-1,5), (-5,1) (-1,-3).



(-1,5) and (-1,-3) are the ends of a vertical line. Since (3,1) is not at the same y-coordinate as either of those, the vertical line must be a diagonal. It has length=8.
Since the diagonal has length 8, its sides have length 4√2, giving an area of 32.
Knowing that the other diagonal is horizontal and has length=8, it should be easy to plot the missing vertex and draw the square.
For what it's worth, the diagonal is a line segment joining two non-consecutive vertices, not sides.

LOL i wished i have explained well. *5th grader here*