Answers

2014-11-12T20:40:20+08:00
4 +  \sqrt{4x^2+3x} = 2x
transpose 4 to the right
 \sqrt{4x^2+3x} = 2x - 4
square both sides of the equation
4x^2 + 3x = (2x-4)^2
4x^2 + 3x = 4x^2 - 16x + 16
4x^2 - 4x^2 + 3x + 16x = 16
3x + 16x = 16
19x = 16
x =  \frac{16}{19}
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