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## Answers

'x +2' be the 2nd number

'x+4' be the 3rd number

x +( x + 2) + (x + 4) = 126

combine like terms

x + x + x = 126 - 2 - 4

3x = 120

x = 40

x+2 = 40 + 2

= 42

The largest integer is represented by x+4

x + 4 = 40 + 4

= 44

Therefore the numbers are 40,42, and 44

**. The largest integer is 44.**

N+(n+2)+(n+4) = 126

3n = 126 -6

3n = 120

n = 40

n+2 = 42

n+4 = 44 is the largest even integer

3n = 126 -6

3n = 120

n = 40

n+2 = 42

n+4 = 44 is the largest even integer