p.s. If there is a part in my solution that you did not understand, please don't hesitate to ask :)

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p.s. If there is a part in my solution that you did not understand, please don't hesitate to ask :)

Log in to add a comment

(x-1)^2 + x^2 + (x+1)^2 = 110

(x^2 - 2x + 1) + x^2 + (x^2 + 2x + 1) = 110

3x^2 + 2 = 110

3x^2 = 108

x^2 = 36

x = +/- 6

thus the consecutive integers can be:

A: {5, 6, 7}

B: {-7, -6, -5}

Hope this helps :)