Answers

2014-05-23T22:07:13+08:00

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Let x and x+1 be the consecutive integers

x + x+1 > 57

2x + 1 > 57

2x > 56

x > 28

The two consecutive integers with the least sum that satisfies the inequality are 29 and 30 ( 29+30 = 59 > 57 )
1 3 1
2014-05-25T13:22:13+08:00

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
X+x>57
2x>57
2xdivided by two and 57 divided by two
X>28
0