# Solve the length of a rectangular lot is three times its width . If the length is decreased by 20 feet and the width is increased by 10 feet, the area is increased by 200 feet. find the dimensions

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by falalala

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by falalala

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L=3w

(l-20)(w+10)=A+200

(3w-20)(w+10)=A+200

10w-400=0

10w=400

w=40

l=3w

l=3(40)

l=120

Therefore the length is 120 and the width is 40

(l-20)(w+10)=A+200

(3w-20)(w+10)=A+200

10w-400=0

10w=400

w=40

l=3w

l=3(40)

l=120

Therefore the length is 120 and the width is 40