# A marble rolls off horizontally from the edge of a tabletop 1.50 m above the floor. It strikes the floor 2.0 m from the base of the table. How long does it take the marble to reach the floor? What is its initial speed?

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to find the time,

you derive a formula from this: d=Vt + (0.5)(a)(t^2)

d-distance t-time

V- initial velocity a-acceleration due to gravity

-1.50m=(0m/s)(t) + (0.5)(-9.8 m/s^2)(t^2) plug it in.

-1.50m= (-4.9 m/s^2)(t^2) Isolate t

(-1.50m)/(-4.9 m/s^2)=t^2

7.35 s=t^2 square root the evreything.

2.71108834 s= t

2.7 s= t

It takes approx. 2.7 seconds.