# One side of an isosceles triangle whose perimeter is 42 units measures 10 units. find the area of the triangle

2
by renzton

2014-11-19T17:20:09+08:00

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P=2s+b
s-side
b=base
42=2(10)+b
42=20+b
b=22 units

There is a theorem in Math, which is that the side is the same as the radius.

Diameter is twice the radius so:
diameter=20 units.

The diameter represents the altitude of the triangle
A=1/2bh
A=1/2(22)(10)
A=1/2(220)
A=110 units²

Hope this helps =)
2014-11-21T00:32:55+08:00

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Sol'n:
P=a+b+c
42=10+b+c  -----(eq.1)
Since Isosceles triangle.Therefore i can say that (b=c).
42=10+2b
b= 16 units
c=16 units

A=(0.5)(10)(√16²-5²)
A=76 square units.