# Three vertices of a parallelogram are (0.-1), (2,5), (-5,-3). find the area and draw the parallelogram?

2
by inosenseexsors
I mean *area
lol sorry for that.

Easy way:
Verify the 4th vertex by drawing on a graphing paper.
The count the total of squares it occupies.
The only problem with this is that you should draw the side accurately..
I can't so I chose to compute. :))

2014-01-09T14:29:25+08:00
But parallelograms have 4 vertices. Try solving for it first.
Then draw it. The formula for the area will also depend on what kind of parallelogram it is. :)
The 4th vertex should be on (-3, 2)
If my computation is right, the are should be 16.
If not, it should at least be somewhere near, :)
If my computation is right, the are should be 16.
If not, it should at least be somewhere near. :)
2014-01-09T18:21:40+08:00
First, you need to find the 4th vertex. To find that, you need to find the slope from point (2,5) and point (0,-1).

Slope is rise over run or (y2-y1) over (x2-x1). The slope is 6/2. So from point (-5,-3) you need to count 2 spaces to the right of -5 which is equal to (-3). Count 6 spaces to the to of -3 which will be equal to (+3). So the 4h point/vertex is found on (-3,3).

To find the area use the matrix form. I'll attach a picture for you