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David currently has a square garden. He wants to redesign his garden and make it into a rectangle with a length that is 3 feet shorter than twice its

width. He decides that the perimeter should be 60 feet. Determine the dimensions, in feet, of his new garden.



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Let x be the width of the rectangle
      2x-3 will be the length

The perimeter of a rectangle is equal to twice the sum of its length and width.
P = 2(x + 2x-3) = 60

2x + 4x -6 = 60
6x -6 = 60
6x = 66
x = 11

Therefore, 11 ft and 19 ft are the width and length, respectively, of the rectangle.
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