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A boat travels at 4 km in 20 min with the current. The return trip takes 24 min. Find the speed of the current and the speed of the boat in still water?

Let 'x' be the speed of the boat 'y' be the speed of the current ------------------------ -the boat travels 4km in 20min with the current x + y = 4km/20min x + y = 0.2km/min ------equation 1 ----------------------- -the boat took 24min of travel against the current x - y = 4km/24min x - y = 0.1667km/min ------equation 2 ---------------------- Add equations 1 and 2 x + y = 0.2 + x - y = 0.1667 2x = 0.3667 x = 0.18333 km/min x = 183.33 m/min --------------------- substitute x=1.08333 to equation 1 x + y = 0.2 y = 0.2 - x y = 0.2 - 0.18333 y = 0.01667km/min y = 16.67 m/min -------------------- Therefore the speed of the boat is 183.33 m/min and the speed of the current is 16.67 m/min.