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2014-11-29T20:30:26+08:00

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(a+b)^2=64 \\\\ a^2+2ab+b^2=64 \\\\ a^2+2*3+b^2=64 \\\\ a^2+6+b^2=64 \\\\ a^2+b^2=64-6 \\\\ \boxed{\boxed{a^2+b^2=58}}
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2014-11-29T20:48:21+08:00

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
(a+b)²=64
a²+2ab+b2=64
a²+2(3)+b²=64
a²+b²=58

Since ab is 3, then twice the value of ab is 6. Therefore just substitute and then subtract it both sides.

Hope this helps =)
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