# This is the problem ----> "Easter is 5 years older than Denise. Four years ago, She was one year less than twice the age of Denise. How old are They?" Guys, please help me . This is a Math subject. I really need your help! Thanks in advance

2
by Irish30

2014-11-30T18:46:56+08:00

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X is easter
y is denise

x=y+5
x-4=2y-1
y+5-4=2y-1
2=y

Denise is 2 years old and Easter is 7 years old.

Hope this helps =)
2014-11-30T19:01:34+08:00
1. Let x = Denise's present age
x+5= Easter's present age

4 years ago their age will be x-4 for Denise and x=1 for Easter

2. Equation:

x+1= 2 ( x-4) -1

x+1= 2x-8-1
x+1=2x-9
9+1=2x-x
10=x ----> Denise's present age
x+5= 15 ----> Eater's present age

Proof:
10-4= 6----> Denise's past age
15-4=11 -----> Easter's past age

6 times 2 = 12 which answers the sentence: She was one year less than twice the age of Denise