# Find the surface area an lateral area of a right cylinder with circumference of a base of 24π and height of 5

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by pau

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by pau

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so the surface area is area of the base x 2 + area of lateral surface=2piR^2+2piRh

C=2piR A=piR^2 Surface Area=2(452.39)+377

24pi=2piR A=pi(12^2) =1281.78

R=24pi/2pi A=452.39

R=12