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Since the Circumference of the base which is 24pi is also the length of the lateral are then to solve for the Area of the lateral edge simply use A=lw=bh=(24pi)(5)=377

so the surface area is area of the base x 2 + area of lateral surface=2piR^2+2piRh
C=2piR          A=piR^2                      Surface Area=2(452.39)+377
24pi=2piR      A=pi(12^2)                                      =1281.78
R=24pi/2pi     A=452.39
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