Answers

2014-12-13T14:31:48+08:00

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Given\ situation; \\ \boxed{(13r-a)^{2}} \\ \\ Solution; \\ \\ \boxed{\boxed{Formula;\to(a)^{2}+2(a)(b)+(b)^{2}}} \\ \\ (13r)^{2}+2(13r)(-a)+(-a)^{2} \\ \\ 169r^{2}+26r(-a)+a^{2} \\ \\ \boxed{\boxed{169r^{2}-26ra+a^{2}}} \\ \\ Hope\ it\ Helps:) \\ Domini
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2014-12-13T20:07:35+08:00

This Is a Certified Answer

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
(13r-a)^2?
Just think of it that it is like this:
13-squared x r-squared  -a-squared
169  x r-squared  a-squared
=169r^2+a^2
Now, WHY DID -a-squared become positive a-squared?
Answer: Given -3-squared:
We all know that -3-squared is 9.
But, it is just the same with 3-squared and both of them yields 9.
So, simple, we just simplified it, done!

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I am not sure but something on my mind tells me that my answer is wrong. Can a professional please review this because I am not sure, but I think that the answer would be: 16ar^2 - 26ar + a^2. Can the moderator please make things clearer!