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(y-y1)=((y2-y1)/(x2-x1)) (x-x1)

(y-4)=((6-4)/(4-2)) (x-2)

y-4= (1)(x-2)

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thanks for the answer :) but it should be in standard form. but thanks anyway, i really appreciate it.
Ax+By+C=0? uhm we could rewrite it as x-y+2=0 :)
i mean that's the standard form :)
i got it :D thanks.
glad i could help
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