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2014-12-17T22:09:26+08:00

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Let\ x+5\ be\ the\ age\ of\ Gracie. \\ Let\ 2(x+5)\ be\ the\ age\ of\ Shine. \\ \\ Solution; \\ \\ x+5+2(x+5)=41+5+5 \\ \\ x+5+2x+10=51 \\ \\ 3x+15=51 \\ \\ 3x=51-15 \\ \\  \frac{3x}{3}=\frac{36}{3} \\ \\ \boxed{\boxed{x=12}} \\ \\ Solve\ for\ the\ age\ where\ x\to12 \\ \\ Gracie: \\ x+5 \\ \\ 12+5 \\ \\ \boxed{17} \\ \\ Thus,Gracie\ is\ 17\ years\ old\ after\ 5\ years. \\ \\  Shine: \\ 2(x+5) \\ \\ 2(12+5) \\ \\ 2(17) \\ \\ \boxed{34}

Thus,Shine\ is\ 34\ years\ old\ after\ 5\ years. \\ \\ Checking; \\ \\ From\ the\ situation\ "the\ sum\ of\ their\ ages\ is\ 41" \\ This\ mean\ before\ 5\ years... \\ \\ We\ will\ subtract\ their\ ages\ by\ 5. \\ \\ Checking\ Solution; \\ (17-5)+(34-5)=41 \\ \\ 12+29=41 \\ \\ \boxed{41=41}\ \underline{TRUE} \\ \\ Therefore,Shine\ and\ Gracie's\ age\ are\ 34\ and\ 17\ respectively. \\ \\ Hope\ it\ Helps:) \\ Domini
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Yeah, thanks Domini for correcting me! I would not have find my mistake if you did not correct me. I learned that I should review my answers before posting it. Thank you so much!
Hey, in the end, why do we have different answers?
I wonder why....But as of now,I think the given situation has many solutions...Its kinda weird though...