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We have not tackled more of this, but I think this is how to answer it:

Given: 150 tons = total solution of metal and ore 8 - 1/2 % = percentage of metal contained in the solution Asked: How much metal will be obtained by the solution.

Solution: Percentage by mass solute = mass solute / mass solution x 100 8% (maximum) = x / 150 tons x 100 8% / 100 = x / 150 tons x 100 / 100 0. 08 = x /150 0. 08 (150 tons) = x/ 150 tons (150 tons) 12 tons = x = mass solute = mass solute = maximum mass of metal found in the solution, 1/2 % or 0.5 % ( minimum) = x / 150 tons x 100 0. 5 % / 100 = x /150 tons x 100 / 100 0. 005 = x / 150 tons 0. 005 x 150 tons = x/ 150 tons (150 tons) 0. 75 tons = x Therefore, there are 12 tons - 0.75 tons of metal found on the ore if I am not mistaken. (somebody correct me if I am wrong)