Answers

2015-01-09T13:07:14+08:00
 \frac{2}{t} - 2 +  \frac{t}{2(t-2)^2} = 0

Multiply whole equation by variable 't':
2-2t +  \frac{t^2}{2(t-2)^2}  = 0

Multiply whole equation by 2:
4-4t+ \frac{t^2}{(t-2)^2} = 0

Simplify:
 \frac{4(t-2)^2-4t(t-2)^2+t^2}{(t-2)^2} = 0
 \frac{4(t^2-4t+4) + 4t(t^2-4t+4) + t^2}{t^2-4t+4} = 0
 \frac{4t^2-16t+16+4t^3-16t^2+16t+t^2}{t^2-4t+4} = 0
 \frac{4t^3-7t^2+16}{t^2-4t+4} =0


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