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The semicircle of area 50 pi centimeters is inscribed inside a rectangle. The diameter of the semicircle coincides with the length of the rectangle. Find

The semicircle of area 50 pi centimeters is inscribed inside a rectangle. The diameter of the semicircle coincides with the length of the rectangle. Find the area of the rectangle.

What the? huhu~ my solutions not yet finished. :'( why can't I re-edit it again?

Area of a circle = [tex] \pi [/tex]r² Area of a rectangle = length x width

Semicircle: A = [tex] \pi [/tex]r² 2(50 [tex] \pi [/tex])= [tex] \pi [/tex]r² --> I multiplied 50 [tex] \pi [/tex] by 2 since 50 [tex] \pi [/tex] is the area of the semicircle.

Area of a circle = pi r² Area of a rectangle = length x width

Semicircle: A = pi r² 2(50 pi ) = pi r² --> I multiplied 50 pi by 2 since 50 pi is the area of the semicircle

(100 pi = pi r²) pi r² = 100 r = 10 cm

Rectangle: (A = length x width)

length = diameter of the semicircle = 2(10 cm) = 20 cm width = radius of the semicircle = 10 cm

so, A = l x w = 20 (10) = 200 cm

*facepalm* sorry for the unwanted comments... jeez... anyways, the above comment is the REAL solution...

*facepalm* for the 987654321 times, i committed a mistake again.... jeez, I am very sorry. In the comment where I put the real solution - it's answer is 200 cm². not 200 cm... :)