The semicircle of area 50 pi centimeters is inscribed inside a rectangle. The diameter of the semicircle coincides with the length of the rectangle. Find the area of the rectangle.

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The semicircle of area 50 pi centimeters is inscribed inside a rectangle. The diameter of the semicircle coincides with the length of the rectangle. Find the area of the rectangle.

Answers

2015-01-11T15:06:24+08:00
Area of a circle =  \pi
Area of a rectangle = base x height

Semicircle: 
A =  \pi
2(50  \pi )=  \pi r²      --> i multiplied 50  \pi by 2 since 50  \pi

The area of the rectangle is 200 cm². 

For the radius is 10 cm. :)
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What the? huhu~ my solutions not yet finished. :'( why can't I re-edit it again?
Area of a circle = [tex] \pi [/tex]r²
Area of a rectangle = length x width

Semicircle:
A = [tex] \pi [/tex]r²
2(50 [tex] \pi [/tex])= [tex] \pi [/tex]r² --> I multiplied 50 [tex] \pi [/tex] by 2 since 50 [tex] \pi [/tex] is the area of the semicircle.
Area of a circle = pi r²
Area of a rectangle = length x width

Semicircle:
A = pi r²
2(50 pi ) = pi r² --> I multiplied 50 pi by 2 since 50 pi is the area of the semicircle

(100 pi = pi r²) pi
r² = 100
r = 10 cm

Rectangle: (A = length x width)

length = diameter of the semicircle
= 2(10 cm)
= 20 cm
width = radius of the semicircle
= 10 cm

so, A = l x w
= 20 (10)
= 200 cm
*facepalm* sorry for the unwanted comments... jeez... anyways, the above comment is the REAL solution...
*facepalm* for the 987654321 times, i committed a mistake again.... jeez, I am very sorry. In the comment where I put the real solution - it's answer is 200 cm². not 200 cm... :)