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A list of three positive numbers has an average of 6. What is the largest possible number in the list.

Thanks and can you please tell the solution.:)

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by allenverbo

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Thanks and can you please tell the solution.:)

by allenverbo

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Let x be the smallest number

[x+(x+1)+(x+2)]/3 = 6

x+x+1+x+2=18

3x+3=18

3x=18-3

3x=15

x=5

so the three numbers are 5,6 and 7. the largest possible number is 7 :)

[x+(x+1)+(x+2)]/3 = 6

x+x+1+x+2=18

3x+3=18

3x=18-3

3x=15

x=5

so the three numbers are 5,6 and 7. the largest possible number is 7 :)