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2014-06-05T21:58:35+08:00

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This is the formula for the sum of an arithmetic series
 \frac{n}{2} [2 a_{1} +(n-1)d] (d is for the difference and n is for the number of terms)
We substitute  the values
 \frac{n}{2} [50+(n-1)2] = 880
 \frac{n}{2} [50+2n-2]
 \frac{n}{2} [48+2n]

1760=n[48+2n]
1760=48n+ 2n^{2}
0=48+ 2n^{2} -1760
0=(2n+88)(n-20)

2n+88=0
2n=-88
n=-44
which is not possible

n-20=0
n=20

Therefore it will take 20 days
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